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Partial Derivatives 101: A Beginner's Guide

What a partial derivative is, why it matters, and how to compute it fast with power/product/chain rules and fully worked examples.

Published August 11, 20251 min read

If you've learned single‑variable calculus, partial derivatives extend the same ideas to functions with multiple variables. We'll keep it approachable and practical: what they mean, how to compute them, and how they connect to gradients and tangent planes. Try anything here inside MathAI GPT to get instant step‑by‑steps.

1) What is a Partial Derivative?

Suppose f(x, y) depends on two variables. The partial derivative ∂f/∂xmeasures the rate of change of f with respect to x while keeping y fixed (treat y like a constant). Similarly for ∂f/∂y.

  • Read as “partial.”
  • Notation options: f_x, ∂f/∂x, or D_x f.

Limit definition (idea)

∂f/∂x(a,b) = lim_{h→0} [f(a+h,b) - f(a,b)]/h. Hold y=b fixed and take the ordinary derivative in x.

Micro‑example: if f(x,y)=x^2y and y=3, then near x=2 the slope in the x‑direction is ∂f/∂x = 2xy = 12.

2) Fast Rules You Already Know (Treat Others as Constants)

  • Power rule: ∂/∂x (x^n) = n x^{n-1}; constants multiply through.
  • Sum / difference: differentiate term‑by‑term.
  • Product rule (two terms in x): (uv)_x = u_x v + u v_x.
  • Chain rule: if u = u(x, y), then f_x = f_u u_x + f_v v_x for appropriate intermediate variables.
  • Exponential / trig: as usual, but only the variable you're differentiating is “active.”

3) Worked Examples

Example A: Basic polynomial

Let f(x, y) = x^2 y + 3 x y^2 - 5y.

∂f/∂x: treat y constant → 2x y + 3 y^2.

∂f/∂y: treat x constant → x^2 + 6xy - 5.

Example B: Product + chain rule

Let f(x, y) = x\, e^{xy}.

∂f/∂x: product rule → 1 \cdot e^{xy} + x \cdot e^{xy} \cdot y =e^{xy}(1 + xy).

∂f/∂y: only the exponent depends on yx \cdot e^{xy} \cdot x = x^2 e^{xy}.

Example C: Trig and chain rule

Let f(x, y) = sin(x^2 + y).

∂f/∂x: inner x^2 + y has derivative 2x in x cos(x^2 + y) \cdot 2x.

∂f/∂y: inner derivative in y is 1 cos(x^2 + y).

4) Mixed Partials and Clairaut's Theorem (Idea Only)

Mixed partials differentiate in two orders, e.g., f_{xy} = ∂/∂y (f_x) andf_{yx} = ∂/∂x (f_y). If f is “nice enough” (continuous partials nearby), these are equal: f_{xy} = f_{yx}.

5) Directional Derivatives and the Gradient

For a unit direction vector \u005E{u} (pronounced “u‑hat”), the directional derivative isD_u f = ∇f · \u005E{u}. The gradient ∇f = ⟨f_x, f_y⟩ points toward the steepest increase; its magnitude |∇f| is the steepest rate.

6) Gradient and Tangent Plane (Why Partials Matter)

The gradient collects first partials: ∇ f = ⟨ f_x, f_y ⟩. At a point (a, b), the linear approximation (tangent plane to the surface z = f(x, y)) is

L(x, y) = f(a, b) + f_x(a, b)(x - a) + f_y(a, b)(y - b)

This is useful for quick estimates and optimization methods.

Numerical example

Let f(x,y)=x^2y + y^3. Then f_x=2xy, f_y=x^2+3y^2. At (1,2): f_x(1,2)=4, f_y(1,2)=13, and f(1,2)=1· 2 + 8 = 10. So the tangent plane isL(x,y)=10 + 4(x-1) + 13(y-2).

7) Critical Points and the Second Derivative Test

Critical points satisfy f_x = 0 and f_y = 0. Let the Hessian beH = [[f_{xx}, f_{xy}], [f_{yx}, f_{yy}]] and defineD = f_{xx} f_{yy} - (f_{xy})^2.

  • D > 0, f_{xx} > 0 → local minimum
  • D > 0, f_{xx} < 0 → local maximum
  • D < 0 → saddle point
  • D = 0 → test inconclusive

Example: f(x,y)=x^2+y^2. The only critical point is (0,0). Here f_{xx}=2, f_{yy}=2, f_{xy}=0 → D=4>0 and f_{xx}>0, so it is a local (and global) minimum.

8) Multivariable Chain Rule (Quick Pattern)

Total differential: df = f_x dx + f_y dy. If x=x(t), y=y(t), thendf/dt = f_x x'(t) + f_y y'(t).

Example

f(x,y)=x^2 y, x=t^2, y=sin,t. Then f_x=2xy, f_y=x^2, x'=2t, y'=cos,t sodf/dt = (2xy)(2t) + (x^2)(cos,t) = 4txy + x^2 cos,t.

9) Tips and Common Pitfalls

  • When taking ∂/∂x, treat y as a constant everywhere (and vice‑versa).
  • Write one line per step for chain/product rules to avoid dropped factors.
  • Check special points (zeros in factors, undefined spots) before simplifying too aggressively.
  • When rules mix: do chain rule for inner functions first, then apply product rule around them.
  • Mind domains: logs need positive inputs; radicals need non‑negatives (unless complex analysis is intended).

10) Practice (Answers Hidden)

  1. f(x, y) = x^3 + x y^2 - 4y: find f_x, f_y.
  2. f(x, y) = e^{x^2 y}: find f_x, f_y.
  3. f(x, y) = (x^2 + y)\,ln(x): find f_x (product + chain).
  4. Critical point classification: f(x,y)=x^2- y^2. Find critical points and use D = f_{xx} f_{yy} - (f_{xy})^2 to classify.
Show answers

1. f_x = 3x^2 + y^2, f_y = 2xy - 4.

2. f_x = e^{x^2 y} (2xy), f_y = e^{x^2 y} (x^2).

3. f_x = (2x)ln x + (x^2 + y)\cdot (1/x).

4. f_x=2x, f_y=-2y so only critical point is (0,0). f_{xx}=2, f_{yy}=-2, f_{xy}=0 → D = -4 < 0 so saddle point.

Next Step

Open the partial derivative calculator and paste a function you're studying (e.g., f(x,y) = x e^{xy} + y^3). Ask for: the first partials, the gradient at a point you choose, and the tangent plane at that point.

Bonus: Ask for a quick visual sketch description of level curves near your point.